(a/9)-(a/5)=(-4/3)

Solution for (a/9)-(a/5)=(-4/3) equation:

(a/9)-(a/5)=(-4/3)

We move all terms to the left:

(a/9)-(a/5)-((-4/3))=0

We add all the numbers together, and all the variables

(+a/9)-(+a/5)-((-4/3))=0

We get rid of parentheses

a/9-a/5-((-4/3))=0

We calculate fractions


(-81a^2)/()+45a^2/()+()/()=0

We add all the numbers together, and all the variables

(-81a^2)/()+45a^2/()+1=0

We multiply all the terms by the denominator


(-81a^2)+45a^2+1*()=0

We add all the numbers together, and all the variables

45a^2+(-81a^2)=0

We get rid of parentheses

45a^2-81a^2=0

We add all the numbers together, and all the variables

-36a^2=0

a = -36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-36)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{-72}=0$