15+2(x-2)=-10-(2x+1)

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Solution for 15+2(x-2)=-10-(2x+1) equation:



15+2(x-2)=-10-(2x+1)
We move all terms to the left:
15+2(x-2)-(-10-(2x+1))=0
We multiply parentheses
2x-(-10-(2x+1))-4+15=0
We calculate terms in parentheses: -(-10-(2x+1)), so:
-10-(2x+1)
determiningTheFunctionDomain -(2x+1)-10
We get rid of parentheses
-2x-1-10
We add all the numbers together, and all the variables
-2x-11
Back to the equation:
-(-2x-11)
We add all the numbers together, and all the variables
2x-(-2x-11)+11=0
We get rid of parentheses
2x+2x+11+11=0
We add all the numbers together, and all the variables
4x+22=0
We move all terms containing x to the left, all other terms to the right
4x=-22
x=-22/4
x=-5+1/2

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