(n-5/n+1)=(n-7/n-2)

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Solution for (n-5/n+1)=(n-7/n-2) equation: 



(n-5/n+1)=(n-7/n-2)

We move all terms to the left:

(n-5/n+1)-((n-7/n-2))=0



Domain of the equation: n+1)!=0

n∈R





Domain of the equation: n-2))!=0

n∈R



We get rid of parentheses

n-5/n-((n-7/n-2))+1=0

We calculate fractions


n+(-5n)/n^2+(-((n-7*n)/n^2+1=0

We add all the numbers together, and all the variables

n+(-5n)/n^2+(-((-6n)/n^2+1=0

We calculate fractions

We do not support enpression: n^4

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