2(m+80+50)=3(m+30+50)

Solution for 2(m+80+50)=3(m+30+50) equation:

2(m+80+50)=3(m+30+50)

We move all terms to the left:

2(m+80+50)-(3(m+30+50))=0

We add all the numbers together, and all the variables

2(m+130)-(3(m+80))=0

We multiply parentheses

2m-(3(m+80))+260=0


We calculate terms in parentheses: -(3(m+80)), so:

3(m+80)

We multiply parentheses

3m+240

Back to the equation:

-(3m+240)


We get rid of parentheses

2m-3m-240+260=0

We add all the numbers together, and all the variables

-1m+20=0

We move all terms containing m to the left, all other terms to the right

-m=-20

m=-20/-1

m=+20