2(m+80)+50=3(m+50)-70

Solution for 2(m+80)+50=3(m+50)-70 equation:

2(m+80)+50=3(m+50)-70

We move all terms to the left:

2(m+80)+50-(3(m+50)-70)=0

We multiply parentheses

2m-(3(m+50)-70)+160+50=0


We calculate terms in parentheses: -(3(m+50)-70), so:

3(m+50)-70

We multiply parentheses

3m+150-70

We add all the numbers together, and all the variables

3m+80

Back to the equation:

-(3m+80)


We add all the numbers together, and all the variables

2m-(3m+80)+210=0

We get rid of parentheses

2m-3m-80+210=0

We add all the numbers together, and all the variables

-1m+130=0

We move all terms containing m to the left, all other terms to the right

-m=-130

m=-130/-1

m=+130