2(m+80)+50=3(m+30+50)-70

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Solution for 2(m+80)+50=3(m+30+50)-70 equation: 



2(m+80)+50=3(m+30+50)-70

We move all terms to the left:

2(m+80)+50-(3(m+30+50)-70)=0

We add all the numbers together, and all the variables

2(m+80)-(3(m+80)-70)+50=0

We multiply parentheses

2m-(3(m+80)-70)+160+50=0



We calculate terms in parentheses: -(3(m+80)-70), so:

3(m+80)-70

We multiply parentheses

3m+240-70

We add all the numbers together, and all the variables

3m+170

Back to the equation:

-(3m+170)



We add all the numbers together, and all the variables

2m-(3m+170)+210=0

We get rid of parentheses

2m-3m-170+210=0

We add all the numbers together, and all the variables

-1m+40=0

We move all terms containing m to the left, all other terms to the right

-m=-40

m=-40/-1

m=+40

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