13=-3(y-5)+y

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Solution for 13=-3(y-5)+y equation: 



13=-3(y-5)+y

We move all terms to the left:

13-(-3(y-5)+y)=0



We calculate terms in parentheses: -(-3(y-5)+y), so:

-3(y-5)+y

We add all the numbers together, and all the variables

y-3(y-5)

We multiply parentheses

y-3y+15

We add all the numbers together, and all the variables

-2y+15

Back to the equation:

-(-2y+15)



We get rid of parentheses

2y-15+13=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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