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=-0.02Y^2+12Y+8
We move all terms to the left:
-(-0.02Y^2+12Y+8)=0
We get rid of parentheses
0.02Y^2-12Y-8=0
a = 0.02; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·0.02·(-8)
Δ = 144.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{144.64}}{2*0.02}=\frac{12-\sqrt{144.64}}{0.04} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{144.64}}{2*0.02}=\frac{12+\sqrt{144.64}}{0.04} $
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