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4/5x-1=-3/2x+4
We move all terms to the left:
4/5x-1-(-3/2x+4)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x+4)!=0We get rid of parentheses
x∈R
4/5x+3/2x-4-1=0
We calculate fractions
8x/10x^2+15x/10x^2-4-1=0
We add all the numbers together, and all the variables
8x/10x^2+15x/10x^2-5=0
We multiply all the terms by the denominator
8x+15x-5*10x^2=0
We add all the numbers together, and all the variables
23x-5*10x^2=0
Wy multiply elements
-50x^2+23x=0
a = -50; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-50)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-50}=\frac{-46}{-100} =23/50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-50}=\frac{0}{-100} =0 $
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