3(t+1)=2(6t+3)

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Solution for 3(t+1)=2(6t+3) equation: 



3(t+1)=2(6t+3)

We move all terms to the left:

3(t+1)-(2(6t+3))=0

We multiply parentheses

3t-(2(6t+3))+3=0



We calculate terms in parentheses: -(2(6t+3)), so:

2(6t+3)

We multiply parentheses

12t+6

Back to the equation:

-(12t+6)



We get rid of parentheses

3t-12t-6+3=0

We add all the numbers together, and all the variables

-9t-3=0

We move all terms containing t to the left, all other terms to the right

-9t=3

t=3/-9

t=-1/3

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