132=4(1+4x)

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Solution for 132=4(1+4x) equation: 



132=4(1+4x)

We move all terms to the left:

132-(4(1+4x))=0

We add all the numbers together, and all the variables

-(4(4x+1))+132=0



We calculate terms in parentheses: -(4(4x+1)), so:

4(4x+1)

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

-16x-4+132=0

We add all the numbers together, and all the variables

-16x+128=0

We move all terms containing x to the left, all other terms to the right

-16x=-128

x=-128/-16

x=+8

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