3x+3x=8(1+x)-4(x-1)

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Solution for 3x+3x=8(1+x)-4(x-1) equation: 



3x+3x=8(1+x)-4(x-1)

We move all terms to the left:

3x+3x-(8(1+x)-4(x-1))=0

We add all the numbers together, and all the variables

3x+3x-(8(x+1)-4(x-1))=0

We add all the numbers together, and all the variables

6x-(8(x+1)-4(x-1))=0



We calculate terms in parentheses: -(8(x+1)-4(x-1)), so:

8(x+1)-4(x-1)

We multiply parentheses

8x-4x+8+4

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

6x-4x-12=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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