6y-1+2+2y=3(8-9y)-6(1-3y)

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Solution for 6y-1+2+2y=3(8-9y)-6(1-3y) equation: 



6y-1+2+2y=3(8-9y)-6(1-3y)

We move all terms to the left:

6y-1+2+2y-(3(8-9y)-6(1-3y))=0

We add all the numbers together, and all the variables

6y+2y-(3(-9y+8)-6(-3y+1))-1+2=0

We add all the numbers together, and all the variables

8y-(3(-9y+8)-6(-3y+1))+1=0



We calculate terms in parentheses: -(3(-9y+8)-6(-3y+1)), so:

3(-9y+8)-6(-3y+1)

We multiply parentheses

-27y+18y+24-6

We add all the numbers together, and all the variables

-9y+18

Back to the equation:

-(-9y+18)



We get rid of parentheses

8y+9y-18+1=0

We add all the numbers together, and all the variables

17y-17=0

We move all terms containing y to the left, all other terms to the right

17y=17

y=17/17

y=1

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