6y-5+1+6y=2(7-3y)-3(1-5y)

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Solution for 6y-5+1+6y=2(7-3y)-3(1-5y) equation: 



6y-5+1+6y=2(7-3y)-3(1-5y)

We move all terms to the left:

6y-5+1+6y-(2(7-3y)-3(1-5y))=0

We add all the numbers together, and all the variables

6y+6y-(2(-3y+7)-3(-5y+1))-5+1=0

We add all the numbers together, and all the variables

12y-(2(-3y+7)-3(-5y+1))-4=0



We calculate terms in parentheses: -(2(-3y+7)-3(-5y+1)), so:

2(-3y+7)-3(-5y+1)

We multiply parentheses

-6y+15y+14-3

We add all the numbers together, and all the variables

9y+11

Back to the equation:

-(9y+11)



We get rid of parentheses

12y-9y-11-4=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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