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130n=100n^2-70n
We move all terms to the left:
130n-(100n^2-70n)=0
We get rid of parentheses
-100n^2+130n+70n=0
We add all the numbers together, and all the variables
-100n^2+200n=0
a = -100; b = 200; c = 0;
Δ = b2-4ac
Δ = 2002-4·(-100)·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200}{2*-100}=\frac{-400}{-200} =+2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200}{2*-100}=\frac{0}{-200} =0 $
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