7x-19=2(x+3)+3

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Solution for 7x-19=2(x+3)+3 equation: 



7x-19=2(x+3)+3

We move all terms to the left:

7x-19-(2(x+3)+3)=0



We calculate terms in parentheses: -(2(x+3)+3), so:

2(x+3)+3

We multiply parentheses

2x+6+3

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We get rid of parentheses

7x-2x-9-19=0

We add all the numbers together, and all the variables

5x-28=0

We move all terms containing x to the left, all other terms to the right

5x=28

x=28/5

x=5+3/5

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