2(v+1)+4v=3(2v-1)=8

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Solution for 2(v+1)+4v=3(2v-1)=8 equation: 



2(v+1)+4v=3(2v-1)=8

We move all terms to the left:

2(v+1)+4v-(3(2v-1))=0

We add all the numbers together, and all the variables

4v+2(v+1)-(3(2v-1))=0

We multiply parentheses

4v+2v-(3(2v-1))+2=0



We calculate terms in parentheses: -(3(2v-1)), so:

3(2v-1)

We multiply parentheses

6v-3

Back to the equation:

-(6v-3)



We add all the numbers together, and all the variables

6v-(6v-3)+2=0

We get rid of parentheses

6v-6v+3+2=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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