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100n^2+1n=70n
We move all terms to the left:
100n^2+1n-(70n)=0
We add all the numbers together, and all the variables
100n^2-69n=0
a = 100; b = -69; c = 0;
Δ = b2-4ac
Δ = -692-4·100·0
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-69}{2*100}=\frac{0}{200} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+69}{2*100}=\frac{138}{200} =69/100 $
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