12a+3(1-9a)+10=-24+2(2a-9)

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Solution for 12a+3(1-9a)+10=-24+2(2a-9) equation: 



12a+3(1-9a)+10=-24+2(2a-9)

We move all terms to the left:

12a+3(1-9a)+10-(-24+2(2a-9))=0

We add all the numbers together, and all the variables

12a+3(-9a+1)-(-24+2(2a-9))+10=0

We multiply parentheses

12a-27a-(-24+2(2a-9))+3+10=0



We calculate terms in parentheses: -(-24+2(2a-9)), so:

-24+2(2a-9)

determiningTheFunctionDomain
2(2a-9)-24

We multiply parentheses

4a-18-24

We add all the numbers together, and all the variables

4a-42

Back to the equation:

-(4a-42)



We add all the numbers together, and all the variables

-15a-(4a-42)+13=0

We get rid of parentheses

-15a-4a+42+13=0

We add all the numbers together, and all the variables

-19a+55=0

We move all terms containing a to the left, all other terms to the right

-19a=-55

a=-55/-19

a=2+17/19

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