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120=1/2(4x+15+6x+5
We move all terms to the left:
120-(1/2(4x+15+6x+5)=0
Domain of the equation: 2(4x+15+6x+5)+120!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2(4x+15+6x+5)!=-120
x∈R
-(1/2(10x+20)+120=0
We multiply all the terms by the denominator
-(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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