38=5(2b-3)+3b=1

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Solution for 38=5(2b-3)+3b=1 equation: 



38=5(2b-3)+3b=1

We move all terms to the left:

38-(5(2b-3)+3b)=0



We calculate terms in parentheses: -(5(2b-3)+3b), so:

5(2b-3)+3b

We add all the numbers together, and all the variables

3b+5(2b-3)

We multiply parentheses

3b+10b-15

We add all the numbers together, and all the variables

13b-15

Back to the equation:

-(13b-15)



We get rid of parentheses

-13b+15+38=0

We add all the numbers together, and all the variables

-13b+53=0

We move all terms containing b to the left, all other terms to the right

-13b=-53

b=-53/-13

b=4+1/13

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