11a-2(1+13a)=40-12a

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Solution for 11a-2(1+13a)=40-12a equation: 



11a-2(1+13a)=40-12a

We move all terms to the left:

11a-2(1+13a)-(40-12a)=0

We add all the numbers together, and all the variables

11a-2(13a+1)-(-12a+40)=0

We multiply parentheses

11a-26a-(-12a+40)-2=0

We get rid of parentheses

11a-26a+12a-40-2=0

We add all the numbers together, and all the variables

-3a-42=0

We move all terms containing a to the left, all other terms to the right

-3a=42

a=42/-3

a=-14

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