3(e2-16)=540

Solution for 3(e2-16)=540 equation:

3(e2-16)=540

We move all terms to the left:

3(e2-16)-(540)=0

We add all the numbers together, and all the variables

3(+e^2-16)-540=0

We multiply parentheses

3e^2-48-540=0

We add all the numbers together, and all the variables

3e^2-588=0

a = 3; b = 0; c = -588;
Δ = b2-4ac
Δ = 02-4·3·(-588)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*3}=\frac{-84}{6}
=-14
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*3}=\frac{84}{6}
=14
$