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X+12X^2=36
We move all terms to the left:
X+12X^2-(36)=0
a = 12; b = 1; c = -36;
Δ = b2-4ac
Δ = 12-4·12·(-36)
Δ = 1729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1729}}{2*12}=\frac{-1-\sqrt{1729}}{24} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1729}}{2*12}=\frac{-1+\sqrt{1729}}{24} $
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