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11-5/2x=x+46
We move all terms to the left:
11-5/2x-(x+46)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-5/2x-x-46+11=0
We multiply all the terms by the denominator
-x*2x-46*2x+11*2x-5=0
Wy multiply elements
-2x^2-92x+22x-5=0
We add all the numbers together, and all the variables
-2x^2-70x-5=0
a = -2; b = -70; c = -5;
Δ = b2-4ac
Δ = -702-4·(-2)·(-5)
Δ = 4860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4860}=\sqrt{324*15}=\sqrt{324}*\sqrt{15}=18\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-18\sqrt{15}}{2*-2}=\frac{70-18\sqrt{15}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+18\sqrt{15}}{2*-2}=\frac{70+18\sqrt{15}}{-4} $
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