39(1+11m)=-15+2(m+27)

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Solution for 39(1+11m)=-15+2(m+27) equation: 



39(1+11m)=-15+2(m+27)

We move all terms to the left:

39(1+11m)-(-15+2(m+27))=0

We add all the numbers together, and all the variables

39(11m+1)-(-15+2(m+27))=0

We multiply parentheses

429m-(-15+2(m+27))+39=0



We calculate terms in parentheses: -(-15+2(m+27)), so:

-15+2(m+27)

determiningTheFunctionDomain
2(m+27)-15

We multiply parentheses

2m+54-15

We add all the numbers together, and all the variables

2m+39

Back to the equation:

-(2m+39)



We get rid of parentheses

429m-2m-39+39=0

We add all the numbers together, and all the variables

427m=0

m=0/427

m=0

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