3(1+4b)=-(-8b-5)+2

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Solution for 3(1+4b)=-(-8b-5)+2 equation: 



3(1+4b)=-(-8b-5)+2

We move all terms to the left:

3(1+4b)-(-(-8b-5)+2)=0

We add all the numbers together, and all the variables

3(4b+1)-(-(-8b-5)+2)=0

We multiply parentheses

12b-(-(-8b-5)+2)+3=0



We calculate terms in parentheses: -(-(-8b-5)+2), so:

-(-8b-5)+2

We get rid of parentheses

8b+5+2

We add all the numbers together, and all the variables

8b+7

Back to the equation:

-(8b+7)



We get rid of parentheses

12b-8b-7+3=0

We add all the numbers together, and all the variables

4b-4=0

We move all terms containing b to the left, all other terms to the right

4b=4

b=4/4

b=1

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