9(12+4z)=3(6z-18

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Solution for 9(12+4z)=3(6z-18 equation:



9(12+4z)=3(6z-18
We move all terms to the left:
9(12+4z)-(3(6z-18)=0
We add all the numbers together, and all the variables
9(4z+12)-(3(6z-18)=0
We multiply parentheses
36z-(3(6z-18)+108=0

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