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10x=-50x/10x
We move all terms to the left:
10x-(-50x/10x)=0
Domain of the equation: 10x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
10x+50x/10x=0
We multiply all the terms by the denominator
10x*10x+50x=0
We add all the numbers together, and all the variables
50x+10x*10x=0
Wy multiply elements
100x^2+50x=0
a = 100; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·100·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*100}=\frac{-100}{200} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*100}=\frac{0}{200} =0 $
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