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x(10-5x)=15
We move all terms to the left:
x(10-5x)-(15)=0
We add all the numbers together, and all the variables
x(-5x+10)-15=0
We multiply parentheses
-5x^2+10x-15=0
a = -5; b = 10; c = -15;
Δ = b2-4ac
Δ = 102-4·(-5)·(-15)
Δ = -200
Delta is less than zero, so there is no solution for the equation
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