2(n-3)=-12+4n

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Solution for 2(n-3)=-12+4n equation: 



2(n-3)=-12+4n

We move all terms to the left:

2(n-3)-(-12+4n)=0

We add all the numbers together, and all the variables

2(n-3)-(4n-12)=0

We multiply parentheses

2n-(4n-12)-6=0

We get rid of parentheses

2n-4n+12-6=0

We add all the numbers together, and all the variables

-2n+6=0

We move all terms containing n to the left, all other terms to the right

-2n=-6

n=-6/-2

n=+3

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