3k+12+3k=6(k+2)

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Solution for 3k+12+3k=6(k+2) equation: 



3k+12+3k=6(k+2)

We move all terms to the left:

3k+12+3k-(6(k+2))=0

We add all the numbers together, and all the variables

6k-(6(k+2))+12=0



We calculate terms in parentheses: -(6(k+2)), so:

6(k+2)

We multiply parentheses

6k+12

Back to the equation:

-(6k+12)



We get rid of parentheses

6k-6k-12+12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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