10x-20-8x+40=100+x

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Solution for 10x-20-8x+40=100+x equation: 



10x-20-8x+40=100+x

We move all terms to the left:

10x-20-8x+40-(100+x)=0

We add all the numbers together, and all the variables

10x-8x-(x+100)-20+40=0

We add all the numbers together, and all the variables

2x-(x+100)+20=0

We get rid of parentheses

2x-x-100+20=0

We add all the numbers together, and all the variables

x-80=0

We move all terms containing x to the left, all other terms to the right

x=80

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