2(y-1)-3(y-2)=(y+5)-4(y-3)

Solution for 2(y-1)-3(y-2)=(y+5)-4(y-3) equation:

2(y-1)-3(y-2)=(y+5)-4(y-3)

We move all terms to the left:

2(y-1)-3(y-2)-((y+5)-4(y-3))=0

We multiply parentheses

2y-3y-((y+5)-4(y-3))-2+6=0


We calculate terms in parentheses: -((y+5)-4(y-3)), so:

(y+5)-4(y-3)

We multiply parentheses

(y+5)-4y+12

We get rid of parentheses

y-4y+5+12

We add all the numbers together, and all the variables

-3y+17

Back to the equation:

-(-3y+17)


We add all the numbers together, and all the variables

-1y-(-3y+17)+4=0

We get rid of parentheses

-1y+3y-17+4=0

We add all the numbers together, and all the variables

2y-13=0

We move all terms containing y to the left, all other terms to the right

2y=13

y=13/2

y=6+1/2