0.0399x2+2x+-75=0

Solution for 0.0399x2+2x+-75=0 equation:

0.0399x^2+2x+-75=0

We add all the numbers together, and all the variables

0.0399x^2+2x=0

a = 0.0399; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·0.0399·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*0.0399}=\frac{-4}{0.0798}
=-50+0.01/0.0798
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*0.0399}=\frac{0}{0.0798}
=0
$