(2c-3)+(2c+3)+(4c-5)=31

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Solution for (2c-3)+(2c+3)+(4c-5)=31 equation: 



(2c-3)+(2c+3)+(4c-5)=31

We move all terms to the left:

(2c-3)+(2c+3)+(4c-5)-(31)=0

We get rid of parentheses

2c+2c+4c-3+3-5-31=0

We add all the numbers together, and all the variables

8c-36=0

We move all terms containing c to the left, all other terms to the right

8c=36

c=36/8

c=4+1/2

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