104=3y(2y+2)

Solution for 104=3y(2y+2) equation:

104=3y(2y+2)

We move all terms to the left:

104-(3y(2y+2))=0


We calculate terms in parentheses: -(3y(2y+2)), so:

3y(2y+2)

We multiply parentheses

6y^2+6y

Back to the equation:

-(6y^2+6y)


We get rid of parentheses

-6y^2-6y+104=0

a = -6; b = -6; c = +104;
Δ = b2-4ac
Δ = -62-4·(-6)·104
Δ = 2532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2532}=\sqrt{4*633}=\sqrt{4}*\sqrt{633}=2\sqrt{633}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{633}}{2*-6}=\frac{6-2\sqrt{633}}{-12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{633}}{2*-6}=\frac{6+2\sqrt{633}}{-12}
$