3(u-2)-5=-4(-6u+5)-3u

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Solution for 3(u-2)-5=-4(-6u+5)-3u equation: 



3(u-2)-5=-4(-6u+5)-3u

We move all terms to the left:

3(u-2)-5-(-4(-6u+5)-3u)=0

We multiply parentheses

3u-(-4(-6u+5)-3u)-6-5=0



We calculate terms in parentheses: -(-4(-6u+5)-3u), so:

-4(-6u+5)-3u

We add all the numbers together, and all the variables

-3u-4(-6u+5)

We multiply parentheses

-3u+24u-20

We add all the numbers together, and all the variables

21u-20

Back to the equation:

-(21u-20)



We add all the numbers together, and all the variables

3u-(21u-20)-11=0

We get rid of parentheses

3u-21u+20-11=0

We add all the numbers together, and all the variables

-18u+9=0

We move all terms containing u to the left, all other terms to the right

-18u=-9

u=-9/-18

u=1/2

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