-13(z+2)+5(4z-7)=6(z-5)+9

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Solution for -13(z+2)+5(4z-7)=6(z-5)+9 equation: 



-13(z+2)+5(4z-7)=6(z-5)+9

We move all terms to the left:

-13(z+2)+5(4z-7)-(6(z-5)+9)=0

We multiply parentheses

-13z+20z-(6(z-5)+9)-26-35=0



We calculate terms in parentheses: -(6(z-5)+9), so:

6(z-5)+9

We multiply parentheses

6z-30+9

We add all the numbers together, and all the variables

6z-21

Back to the equation:

-(6z-21)



We add all the numbers together, and all the variables

7z-(6z-21)-61=0

We get rid of parentheses

7z-6z+21-61=0

We add all the numbers together, and all the variables

z-40=0

We move all terms containing z to the left, all other terms to the right

z=40

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