100=(n)+(n)+(n+2)+(n+2)

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Solution for 100=(n)+(n)+(n+2)+(n+2) equation: 



100=(n)+(n)+(n+2)+(n+2)

We move all terms to the left:

100-((n)+(n)+(n+2)+(n+2))=0



We calculate terms in parentheses: -(n+n+(n+2)+(n+2)), so:

n+n+(n+2)+(n+2)

We add all the numbers together, and all the variables

2n+(n+2)+(n+2)

We get rid of parentheses

2n+n+n+2+2

We add all the numbers together, and all the variables

4n+4

Back to the equation:

-(4n+4)



We get rid of parentheses

-4n-4+100=0

We add all the numbers together, and all the variables

-4n+96=0

We move all terms containing n to the left, all other terms to the right

-4n=-96

n=-96/-4

n=+24

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