6y+2(7y+3)=106

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Solution for 6y+2(7y+3)=106 equation: 



6y+2(7y+3)=106

We move all terms to the left:

6y+2(7y+3)-(106)=0

We multiply parentheses

6y+14y+6-106=0

We add all the numbers together, and all the variables

20y-100=0

We move all terms containing y to the left, all other terms to the right

20y=100

y=100/20

y=5

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