3(x+5)=12-12(x-4)

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Solution for 3(x+5)=12-12(x-4) equation: 



3(x+5)=12-12(x-4)

We move all terms to the left:

3(x+5)-(12-12(x-4))=0

We multiply parentheses

3x-(12-12(x-4))+15=0



We calculate terms in parentheses: -(12-12(x-4)), so:

12-12(x-4)

determiningTheFunctionDomain
-12(x-4)+12

We multiply parentheses

-12x+48+12

We add all the numbers together, and all the variables

-12x+60

Back to the equation:

-(-12x+60)



We get rid of parentheses

3x+12x-60+15=0

We add all the numbers together, and all the variables

15x-45=0

We move all terms containing x to the left, all other terms to the right

15x=45

x=45/15

x=3

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