R(x)=x(70-5x)C(x)=160+10x

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Solution for R(x)=x(70-5x)C(x)=160+10x equation: 



(R)=R(70-5R)(R)=160+10R

We move all terms to the left:

(R)-(R(70-5R)(R))=0

We add all the numbers together, and all the variables

R-(R(-5R+70)R)=0



We calculate terms in parentheses: -(R(-5R+70)R), so:

R(-5R+70)R

We multiply parentheses

-5R^3+70R^2

We do not support eRpression: R^3

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