1000(6x-10)=40(315+100x)

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Solution for 1000(6x-10)=40(315+100x) equation: 



1000(6x-10)=40(315+100x)

We move all terms to the left:

1000(6x-10)-(40(315+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(100x+315))=0

We multiply parentheses

6000x-(40(100x+315))-10000=0



We calculate terms in parentheses: -(40(100x+315)), so:

40(100x+315)

We multiply parentheses

4000x+12600

Back to the equation:

-(4000x+12600)



We get rid of parentheses

6000x-4000x-12600-10000=0

We add all the numbers together, and all the variables

2000x-22600=0

We move all terms containing x to the left, all other terms to the right

2000x=22600

x=22600/2000

x=11+3/10

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