9(x-4)-7x=32-2(x+18)

Solution for 9(x-4)-7x=32-2(x+18) equation:

9(x-4)-7x=32-2(x+18)

We move all terms to the left:

9(x-4)-7x-(32-2(x+18))=0

We add all the numbers together, and all the variables

-7x+9(x-4)-(32-2(x+18))=0

We multiply parentheses

-7x+9x-(32-2(x+18))-36=0


We calculate terms in parentheses: -(32-2(x+18)), so:

32-2(x+18)

determiningTheFunctionDomain
-2(x+18)+32

We multiply parentheses

-2x-36+32

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)


We add all the numbers together, and all the variables

2x-(-2x-4)-36=0

We get rid of parentheses

2x+2x+4-36=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8