(1/5)(4z-10)=(4/5)z-2

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Solution for (1/5)(4z-10)=(4/5)z-2 equation: 



(1/5)(4z-10)=(4/5)z-2

We move all terms to the left:

(1/5)(4z-10)-((4/5)z-2)=0



Domain of the equation: 5)(4z-10)!=0

z∈R





Domain of the equation: 5)z-2)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+1/5)(4z-10)-((+4/5)z-2)=0

We multiply parentheses ..

(+4z^2+1/5*-10)-((+4/5)z-2)=0

We calculate fractions

We do not support ezpression: z^3

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