3(4x-5)+8x=2x-9(2x+1)

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Solution for 3(4x-5)+8x=2x-9(2x+1) equation: 



3(4x-5)+8x=2x-9(2x+1)

We move all terms to the left:

3(4x-5)+8x-(2x-9(2x+1))=0

We add all the numbers together, and all the variables

8x+3(4x-5)-(2x-9(2x+1))=0

We multiply parentheses

8x+12x-(2x-9(2x+1))-15=0



We calculate terms in parentheses: -(2x-9(2x+1)), so:

2x-9(2x+1)

We multiply parentheses

2x-18x-9

We add all the numbers together, and all the variables

-16x-9

Back to the equation:

-(-16x-9)



We add all the numbers together, and all the variables

20x-(-16x-9)-15=0

We get rid of parentheses

20x+16x+9-15=0

We add all the numbers together, and all the variables

36x-6=0

We move all terms containing x to the left, all other terms to the right

36x=6

x=6/36

x=1/6

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