28z(z-1)=30z

Solution for 28z(z-1)=30z equation:

28z(z-1)=30z

We move all terms to the left:

28z(z-1)-(30z)=0

We add all the numbers together, and all the variables

-30z+28z(z-1)=0

We multiply parentheses

28z^2-30z-28z=0

We add all the numbers together, and all the variables

28z^2-58z=0

a = 28; b = -58; c = 0;
Δ = b2-4ac
Δ = -582-4·28·0
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-58}{2*28}=\frac{0}{56}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+58}{2*28}=\frac{116}{56}
=2+1/14
$