10-2(y+1)+3(1-y)=y+1

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Solution for 10-2(y+1)+3(1-y)=y+1 equation: 



10-2(y+1)+3(1-y)=y+1

We move all terms to the left:

10-2(y+1)+3(1-y)-(y+1)=0

We add all the numbers together, and all the variables

-2(y+1)+3(-1y+1)-(y+1)+10=0

We multiply parentheses

-2y-3y-(y+1)-2+3+10=0

We get rid of parentheses

-2y-3y-y-1-2+3+10=0

We add all the numbers together, and all the variables

-6y+10=0

We move all terms containing y to the left, all other terms to the right

-6y=-10

y=-10/-6

y=1+2/3

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