42(y+1)-3(2y-5)=29

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Solution for 42(y+1)-3(2y-5)=29 equation: 



42(y+1)-3(2y-5)=29

We move all terms to the left:

42(y+1)-3(2y-5)-(29)=0

We multiply parentheses

42y-6y+42+15-29=0

We add all the numbers together, and all the variables

36y+28=0

We move all terms containing y to the left, all other terms to the right

36y=-28

y=-28/36

y=-7/9

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